Board Thread:Off Topic/@comment-28236282-20161128060141/@comment-27080660-20161202123716

Well, seeing as nobody was able to answer mine, I'll provide an easier one, along with the answer for mine.

Answer:

(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4) The two terms in the numerator are 2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)  and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2) Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3) Dividing the second term with the denominator, you get: -x(x^2-9)^(1/3) (x^2+4)^((-3)/2) So, combining the results(that is adding them), the answer is: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3) -x(x^2-9)^(1/3) (x^2+4)^((-3)/2) Now, for a much easier problem.

2x+3y=z+32

 If x=8 and y=13, solve for z.  